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A container of volume V, contains 0.28 g of N_{2} gas. If same volume of an unknown gas under similar condition of temperature and pressure weighs, 0.44 g, the molecular mass of the gas is2
(1) 22
(3) 66
(2) 44
(4) 88
The answer is (2) show me easy steps?
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A container of volume V, contains 0.28 g of N_{2} gas. If same volume ...
Given Data:
- Volume of the container, V
- Mass of N_{2} gas, 0.28 g
- Mass of the unknown gas, 0.44 g

Calculation:
- The molar mass of N_{2} = 28 g/mol (as N has atomic mass 14)
- Number of moles of N_{2} = Mass/Molar mass = 0.28/28 = 0.01 mol
- Since the volume and conditions are the same for both gases, the number of moles of the unknown gas is also 0.01 mol.
- Mass of the unknown gas = Number of moles * Molar mass
- 0.44 = 0.01 * Molar mass
- Molar mass = 44 g/mol
Therefore, the molecular mass of the unknown gas is 44 g/mol, which corresponds to option (2).
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A container of volume V, contains 0.28 g of N_{2} gas. If same volume of an unknown gas under similar condition of temperature and pressure weighs, 0.44 g, the molecular mass of the gas is2(1) 22(3) 66(2) 44(4) 88The answer is (2) show me easy steps?
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A container of volume V, contains 0.28 g of N_{2} gas. If same volume of an unknown gas under similar condition of temperature and pressure weighs, 0.44 g, the molecular mass of the gas is2(1) 22(3) 66(2) 44(4) 88The answer is (2) show me easy steps? for Humanities/Arts 2025 is part of Humanities/Arts preparation. The Question and answers have been prepared according to the Humanities/Arts exam syllabus. Information about A container of volume V, contains 0.28 g of N_{2} gas. If same volume of an unknown gas under similar condition of temperature and pressure weighs, 0.44 g, the molecular mass of the gas is2(1) 22(3) 66(2) 44(4) 88The answer is (2) show me easy steps? covers all topics & solutions for Humanities/Arts 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A container of volume V, contains 0.28 g of N_{2} gas. If same volume of an unknown gas under similar condition of temperature and pressure weighs, 0.44 g, the molecular mass of the gas is2(1) 22(3) 66(2) 44(4) 88The answer is (2) show me easy steps?.
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